Published by:
CGP EDU Academic Team
Published on: September 13, 2026
Natural length of a spring is 60 cm, and its spring constant is 4000 N/m. A mass of 20 kg is hung from it. The extension produced in the spring is, (Take $g = 9.8 \, m/s^{2}$ )
Text Solution
Verified by ExpertsThe correct answer is:
A
If $X$ is the extension produced in spring.
$ \mathrm{F = kx \Rightarrow x = \frac{F}{k} = \frac{mg}{k} = \frac{20 \times 9.8}{4000} = 4.9 \text{ cm}} $
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A particle moves under the effect of a force F = Cx from $x=0$ to $x = x_1$ . The work done in the …
A cord is used to lower vertically a block of mass M by a distance d with constant downward acceler…
Two springs have their force constant as k 1 and $k_{2}(k_{1} > k_{2})$ . When they are stretched b…
The potential energy of a certain spring when stretched through a distance ‘S’ is 10 joule. The amo…
A position dependent force newton acts on a small body of mass 2 kg and displaces it from to . T…
A body of mass 3 kg is under a force, which causes a displacement in it is given by $S = t^{4} - 3t…